Eenigma wrote:
PNeilson 10 wrote:
So we are getting a semi consistent picture.
Breakdown is the limit on CCTO type material.
Some methods of limiting breakdown have lead to lowering k
So reducing oxygen vacancies lowers leakage but reduces k
So wrap the material in alumina and keep the oxygen vacancies stable and k hi with low breakdown.
I wonder what happens then? Guess I have to ask DW at EEStor.
Excellent post PN. I would take it on step further and say we are getting a consistent picture across the board.
If Northrop adds an alumina shell to this material it's off to the races. I'm sure the designers of this dielectric would also like to have molecular tweezers and align each and every particle for optimum ED results. Perhaps Northup could borrow DW's alumina coating technique as well as the molecular "poling" tweezers.
The other consistent picture we are seeing here is Tom will trash any patent that isn't consistent with his limited understanding of dielectrics.
Well Een, my understanding may be limited, but I will debate it with anyone here and either defend it, or be educated and make it better!
I think you are putting it too strongly. The Northrup patent is about a process for depositing high quality dielectric, and mathching lattice spacing with substrate. It is (I guess) worth something. Obviously the more useful CCTO and related crstals are, the more it is worth. And as is proper it will claim everything under the sun - no-one ever got into trouble ading claims to a patent.
I also think you are over-reading its significance. Does it imply they have somehow got CCTO with high k and 1000X the breakdown of all other high-k CCTO? Seems unlikely to me, and certainly not necessary given the patent.
Since I have a clear understanding of the physical mechanisms and difficulties here, which you and most others here don't share, we may disagree about this. But you would be over-egging the pudding vastly to say that this patent constitutes strong evidence (let alone proof) that CCTO can have ultra-high ED.
Assumptions: 1) E=1/2CV2
(Only dummies assume this)